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Samsung heat pump - data cable issue

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Majordennisbloodnok
(@majordennisbloodnok)
Famed Member Moderator
Joined: 5 years ago
Posts: 1992
 

Posted by: @jamespa

Posted by: @majordennisbloodnok

A resistor won’t clear up noise.

Is that the case? Surely the terminating resistor also reduces the impedance of the circuit, and thus induced currents will generate smaller voltages

 

You may well be right; I am by no means an expert. It’s my understanding, but I am happy to be proven wrong. I’d welcome any electronics experts to wade in at this point.

 


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bobflux
(@bobflux)
Estimable Member Member
Joined: 5 months ago
Posts: 130
 

If it is RS485 (is it?)...

It uses balanced/differential twisted pair link. The idea is to send the signal on one wire, and the inverted signal on the other wire. For example, one wire +5V the other 0V to send "1", and one wire 0V the other +5V to send "0".

Voltage between both wires is called "differential mode" and is your actual signal. Voltage between the average of both wires and receiver ground is called "common mode". In the above example, differential mode is either +5V for "1" or -5V for "0" and common mode is 2.5V.

The idea behind balanced differential transmission is:

1) The receiver compares (or subtracts) voltages on both wires to decode what was transmitted. It does so while doing its best to ignore common mode: shifting both wires' voltage by the same amount doesn't change the result.

2) We want both wires to receive noise in the exact same way, ie common mode, so the receiver can reject it. For this, the wires should have the same impedance, and they should be twisted.

Two parallel wires in a perpendicular electric field receive a noise voltage between them. Twisting the wires cancels that, and also makes more of the noise common mode.

In a variable magnetic field, induced current in a wire loop is proportional to loop area. Area between the wires is tiny, so for all intents and purposes, there is almost no induced current in the loop formed by the two wires. However, the cable is long, and it forms a very large loop with the other return wire, which is Protection Earth. Therefore, induced current problems are mostly common mode, within the loop Device1 - comms cable - Device2 - Earth - Device1. The solution to this is to use isolated RS485 transmitters to break the loop (this is very common), and connect the cable shield at both ends to ensure both RS485 chips have a common ground and don't see harmful common mode voltages. Ironically this is almost never done, all you get is two terminals "A" and "B" and nothing to connect the shield, which makes the shield mostly useless.

The termination resistor is to avoid signal reflections in the transmission line, which only cause problems if the rise time of the signal is quicker than propagation time in the transmission line. This is not usually an issue at the low baud rates used in these links.



   
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